"景先生毕设|www.jxszl.com

超经典SQL练习题,涵盖所有常见基础

2022-11-29 12:09编辑: www.jxszl.com景先生毕设
超经典SQL练习题,涵盖所有常见基础

--1.学生表
Student(S#,Sname,Sage,Ssex) --S# 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
--2.课程表
Course(C#,Cname,T#) --C# --课程编号,Cname 课程名称,T# 教师编号

--3.教师表
Teacher(T#,Tname)--T# 教师编号,Tname 教师姓名


--4.成绩表
SC(S#,C#,score)--S# 学生编号,C# 课程编号,score 分数



创建测试数据

学生表 Student
create table Student(S# varchar(10),Sname nvarchar(10),Sage datetime,Ssex nvarchar(10))
insert into Student values('01' , N'赵雷' , '1990-01-01' , N'男')
insert into Student values('02' , N'钱电' , '1990-12-21' , N'男')
insert into Student values('03' , N'孙风' , '1990-05-20' , N'男')
insert into Student values('04' , N'李云' , '1990-08-06' , N'男')
insert into Student values('05' , N'周梅' , '1991-12-01' , N'女')
insert into Student values('06' , N'吴兰' , '1992-03-01' , N'女')
insert into Student values('07' , N'郑竹' , '1989-07-01' , N'女')
insert into Student values('08' , N'王菊' , '1990-01-20' , N'女')


科目表 Course
create table Course(C# varchar(10),Cname nvarchar(10),T# varchar(10))
insert into Course values('01' , N'语文' , '02')
insert into Course values('02' , N'数学' , '01')
insert into Course values('03' , N'英语' , '03')

教师表 Teacher
create table Teacher(T# varchar(10),Tname nvarchar(10))
insert into Teacher values('01' , N'张三')
insert into Teacher values('02' , N'李四')
insert into Teacher values('03' , N'王五')

成绩表 SC
create table SC(S# varchar(10),C# varchar(10),score decimal(18,1))
insert into SC values('01' , '01' , 80)
insert into SC values('01' , '02' , 90)
insert into SC values('01' , '03' , 99)
insert into SC values('02' , '01' , 70)
insert into SC values('02' , '02' , 60)
insert into SC values('02' , '03' , 80)
insert into SC values('03' , '01' , 80)
insert into SC values('03' , '02' , 80)
insert into SC values('03' , '03' , 80)
insert into SC values('04' , '01' , 50)
insert into SC values('04' , '02' , 30)
insert into SC values('04' , '03' , 20)
insert into SC values('05' , '01' , 76)
insert into SC values('05' , '02' , 87)
insert into SC values('06' , '01' , 31)
insert into SC values('06' , '03' , 34)
insert into SC values('07' , '02' , 89)
insert into SC values('07' , '03' , 98)


50道练习题题目及答案
--1 查询“ 01 ”课程比" 02 "课程成绩高的学生的信息及课程分数  
select A.*,B.C#,B.score from (select * from SC where C#='01')A   
left join(select * from SC where C#='02')B   
on A.S#=B.S#   
where A.score>B.score  

 --1.1 查询同时存在" 01 "课程和" 02 "课程的情况  
select * from (select * from SC where C#='01')A   
left join (select * from SC where C#='02')B on A.S#=B.S#  
where B.S# is not null  

  --1.2 查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为null)  
select * from (select * from SC where C#='01')A  
left join (select * from SC where C#='02')B on A.S#=B.S#  

  --1.3 查询不存在" 01 "课程但存在" 02 "课程的情况  
select * from SC where C#='02'and S# not in(select S# from SC where C#='01')  

 --2. 查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩   
select A.S#,B.Sname,A.dc from(select S#,AVG(score)dc from SC group by S#)A  
left join Student B on A.S#=B.S# where A.dc>=60  

  --3. 查询在 SC 表存在成绩的学生信息  
select * from Student where S# in (select distinct S# from SC)  

  --4. 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为null)  
select B.S#,B.Sname,A.选课总数,A.总成绩 from  
(select S#,COUNT(C#)选课总数,sum(score)总成绩 from SC group by S#)A  
right join Student B on A.S#=B.S#  

--4.1 查有成绩的学生信息   
select A.S#,B.Sname,A.选课总数,A.总成绩 from  
(select S#,COUNT(C#)选课总数,sum(score)总成绩 from SC group by S#)A  
left join Student B on A.S#=B.S#  
 
 --5.查询「李」姓老师的数量  
select COUNT(*)李姓老师数量 from Teacher where Tname like '李%'  
 
--6.查询学过「张三」老师授课的同学的信息   
select * from Student  
where S# in(select distinct S# from SC   
where C#=(select C# from Course   
where T#=(select T# from Teacher where Tname='张三')))  

--7.查询没有学全所有课程的同学的信息  
select * from Student where S# in(select S# from SC group by S# having COUNT(C#)<3)  
 
 --8. 查询至少有一门课与学号为" 01 "的同学所学相同的同学的信息    
select * from Student   
where S# in(select distinct S# from SC where C# in(select C# from SC where S#='01')  
)  

  --9. 查询和" 01 "号的同学学习的课程完全相同的其他同学的信息   
select * from Student   
where S# in(select S# from SC where C# in(select distinct C# from SC where S#='01') and S#<>'01'  
group by S#  
having COUNT(C#)>=3)  

--10. 查询没学过「张三」老师讲授的任一门课程的学生姓名    
select Sname from Student   
where S# not in(select S# from SC   
where C# in(select C# from Course where T# in(select T# from Teacher where Tname='张三')  
)  
)
 
--11.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩   
select A.S#,A.Sname,B.平均成绩 from Student A right join  
(select S#,AVG(score)平均成绩 from SC where score<60 group by S# having COUNT(score)>=2)B  
on A.S#=B.S#

--12.检索" 01 "课程分数小于 60 ,按分数降序排列的学生信息  
select S#,score from SC where C#='01' and score<60 order by score desc  

--13. (静态写法)按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩  
select S#,max(case C# when '01' then score else 0 end)'01',  
max(case C# when '02' then score else 0 end)'02',  
MAX(case C# when '03' then score else 0 end)'03',AVG(score)平均分 from SC  
group by S# order by 平均分 desc  

--14.查询各科成绩最高分、最低分和平均分:  
    --以如下形式显示:课程 ID ,课程 name ,最高分,最低分,平均分,及格率,中等率,优良率,优秀率  
    --及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
select distinct A.C#,Cname,最高分,最低分,平均分,及格率,中等率,优良率,优秀率 from SC A  
left join Course on A.C#=Course.C#  
left join (select C#,MAX(score)最高分,MIN(score)最低分,AVG(score)平均分 from SC group by C#)B on A.C#=B.C#  
left join (select C#,(convert(decimal(5,2),(sum(case when score>=60 then 1 else 0 end)*1.00)/COUNT(*))*100)及格率 from SC group by C#)C on A.C#=C.C#  
left join (select C#,(convert(decimal(5,2),(sum(case when score >=70 and score<80 then 1 else 0 end)*1.00)/COUNT(*))*100)中等率 from SC group by C#)D on A.C#=D.C#  
left join (select C#,(convert(decimal(5,2),(sum(case when score >=80 and score<90 then 1 else 0 end)*1.00)/COUNT(*))*100)优良率 from SC group by C#)E on A.C#=E.C#  
left join (select C#,(convert(decimal(5,2),(sum(case when score >=90 then 1 else 0 end)*1.00)/COUNT(*))*100)优秀率   
from SC group by C#)F on A.C#=F.C#  
 
--15. 按各科成绩进行排序,并显示排名,Score 重复时保留名次空缺   
select *,RANK()over(order by score desc)排名 from SC   

--15.1 按各科成绩进行排序,并显示排名,Score 重复时合并名次  
select *,DENSE_RANK()over(order by score desc)排名 from SC  

--16. 查询学生的总成绩,并进行排名,总分重复时保留名次空缺  
select *,RANK()over(order by 总成绩 desc)排名 from(  
select S#,SUM(score)总成绩 from SC group by S#)A  

--16.1 查询学生的总成绩,并进行排名,总分重复时不保留名次空缺    
select *,dense_rank()over(order by 总成绩 desc)排名 from(  
select S#,SUM(score)总成绩 from SC group by S#)A  

--17. 统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0] 及所占百分比   
select distinct A.C#,B.Cname,C.[100-85],C.所占百分比,D.[85-70],D.所占百分比,E.[70-60],E.所占百分比,F.[60-0],F.所占百分比  
from SC A   
left join Course B ON A.C#=B.C#  
left join (select C#,sum(case when score>85 and score<=100 then 1 else null end)[100-85],  
convert(decimal(5,2),(sum(case when score>85 and score<100 then 1 else null end))*1.00/COUNT(*))*100 所占百分比 from SC group by C#)C on A.C#=C.C#  
left join (select C#,sum(case when score>70 and score<=85 then 1 else null end)[85-70],  
convert(decimal(5,2),(sum(case when score>70 and score<=85 then 1 else null end))*1.00/COUNT(*))*100 所占百分比 from SC group by C#)D on A.C#=D.C#  
left join (select C#,sum(case when score>60 and score<=70 then 1 else null end)[70-60],  
convert(decimal(5,2),(sum(case when score>60 and score<=70 then 1 else null end))*1.00/COUNT(*))*100 所占百分比 from SC group by C#)E on A.C#=E.C#  
left join (select C#,sum(case when score>0 and score<=60 then 1 else null end)[60-0],  
convert(decimal(5,2),(sum(case when score>0 and score<=60 then 1 else null end))*1.00/COUNT(*))*100 所占百分比 from SC group by C#)F on A.C#=F.C#  

--18. 查询各科成绩前三名的记录(方法 1)    
select * from(select *,rank()over (partition by C# order by score desc)A from SC)B where B.A<=3  

--18. 查询各科成绩前三名的记录(取 a 的最高分与本表比较)(方法 2)   
select a.S#,a.C#,a.score from SC a   
left join SC b on a.C#=b.C# and a.score<b.score  
group by a.S#,a.C#,a.score  
having COUNT(b.S#)<3  
order by a.C#,a.score desc  

--18. 查询各科成绩前三名的记录(取 a)(方法 3)  
select * from SC a where (select COUNT(*)from SC where C#=a.C# and score>a.score)<3  
order by a.C#,a.score desc  

--19. 查询每门课程被选修的学生数   
select C#,COUNT(S#)学生数 from SC group by C#  

--20. 查询出只选修两门课程的学生学号和姓名  
select S#,Sname from Student   
where S# in(select S# from(select S#,COUNT(C#)课程数 from SC group by S#)A where A.课程数=2)  
 
--21. 查询男生、女生人数  
select Ssex,COUNT(Ssex)人数 from Student group by Ssex  

--22. 查询名字中含有「风」字的学生信息
select * from Student where Sname like '%风%'   
 
--23. 查询同名同性学生名单,并统计同名人数   
select A.*,B.同名人数 from Student A  
left join (select Sname,Ssex,COUNT(*)同名人数 from Student group by Sname,Ssex)B   
on A.Sname=B.Sname and A.Ssex=B.Ssex  
where B.同名人数>1  

--24.查询 1990 年出生的学生名单  
select * from Student where YEAR(Sage)=1990  

--25. 查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列  
select C#,AVG(score)平均成绩 from SC group by C# order by 平均成绩 desc,C#  

--26. 查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩    
select A.S#,A.Sname,B.平均成绩 from Student A  
left join (select S#,AVG(score)平均成绩 from SC group by S#)B on A.S#=B.S#  
where B.平均成绩>85  

-- 27. 查询课程名称为「数学」,且分数低于 60 的学生姓名和分数  
select B.Sname,A.score from(select * from SC where score<60 and C#=(select C# from Course where Cname='数学'))A  
left join Student B on A.S#=B.S#  
 
-- 28. 查询所有学生的课程及分数情况(存在学生没成绩,没选课的情况)  
select A.S#,B.C#,B.score from Student A left join SC B on A.S#=B.S#  

-- 29. 查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
select A.Sname,D.Cname,D.score from   
(select B.*,C.Cname from(select * from SC where score>70)B left join Course C on B.C#=C.C#)D   
left join Student A on D.S#=A.S#  
 
-- 30. 查询不及格的课程
select * from SC where score<60  
 
--31. 查询课程编号为01且课程成绩在80分以上的学生的学号和姓名  
select A.S#,B.Sname from (select * from SC where score>80 and C#=01)A  
left join Student B on A.S#=B.S#  

--32. 求每门课程的学生人数   
select C#,COUNT(*)学生人数 from SC group by C#  

--33. 成绩不重复,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩   
select top 1* from SC   
where C#=(select C# from Course where T#=(select T# from Teacher where Tname='张三'))   
order by score desc  

--34. 成绩有重复的情况下,查询选修「张三」老师所授课程的学生中,成绩最高的学生信息及其成绩   
select *from(select *,DENSE_RANK()over (order by score desc)A   
from SC   
where C#=(select C# from Course where T#=(select T# from Teacher where Tname='张三')))B  
where B.A=1  

--35. 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩  
select C.S#,max(C.C#)C#,max(C.score)score from SC C   
left join(select S#,avg(score)A from SC group by S#)B   
on C.S#=B.S#  
where C.score=B.A  
group by C.S#  
having COUNT(0)=(select COUNT(0)from SC where S#=C.S#)  
 
--36. 查询每门功成绩最好的前两名    
select * from  
(select *,ROW_NUMBER()over(partition by C# order by score desc)A from SC)B  
where B.A<3  

--37.统计每门课程的学生选修人数(超过5人的课程才统计)。  
    --要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列   
select C#,COUNT(S#)选修人数 from SC   
group by C#  
having COUNT(S#)>5  
order by 选修人数 desc,C#  

--38. 检索至少选修两门课程的学生学号    
select S# from SC  
group by S#  
having COUNT(C#)>=2  

--39. 查询选修了全部课程的学生信息   
select S# from SC   
group by S#   
having count(C#)=(select distinct COUNT(0)a from Course)  

--40. 查询各学生的年龄,只按年份来算  
select S#,datediff(yy,Sage,GETDATE())年龄 from Student  

--41. 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一  
    --方法是把时间转化成 Int 格式来做条件比较大小,判断是否超期,   
select *,(case when convert(int,'1'+substring(CONVERT(varchar(10),Sage,112),5,8))  
<convert(int,'1'+substring(CONVERT(varchar(10),GETDATE(),112/*112是将格式转化为yymmdd*/),5,8))   
then datediff(yy,Sage,GETDATE())   
else datediff(yy,Sage,GETDATE())-1   
end)age   
from Student   

--42. 查询本周过生日的学生  
    --方法:采取将生日转化为当年日期,再转化为本年中的第几个星期进行判断搜出结果  
select *,(case when datename(wk,convert(datetime,(convert(varchar(10),year(GETDATE()))+substring(convert(varchar(10),Sage,112),5,8))))=DATENAME(WK,GETDATE())   
then 1 else 0 end)生日提醒  
from Student  

--43. 查询下周过生日的学生  
select *,(case when datename(wk,convert(datetime,(convert(varchar(10),year(GETDATE()))+  
substring(convert(varchar(10),Sage,112),5,8))))=DATENAME(WK,GETDATE())+1   
then 1 else 0 end)生日提醒  
from Student  

--44. 查询本月过生日的学生  
select *,(case when month(convert(datetime,(convert(varchar(10),year(GETDATE()))+substring(convert(varchar(10),Sage,112),5,8))))=month(GETDATE())  
then 1 else 0 end)生日提醒  
from Student  

--45. 查询下月过生日的学生  
select *,(case when month(convert(datetime,(convert(varchar(10),year(GETDATE()))+substring(convert(varchar(10),Sage,112),5,8))))=month(GETDATE())+1  
then 1 else 0 end)生日提醒  
from Student 
原文链接:http://www.jxszl.com/biancheng/shujuku/83449.html